PUNJAB PUBLIC SERVICE COMMISSION
COMBINED COMPETITIVE EXAMINATION FOR
RECRUITMENT TO THE POSTS OF
PROVINCIAL MANAGEMENT SERVICE-2023
BOTANY (PAPER-II)
TIME ALLOWED: THREE HOURS
MAXIMUM MARKS: 100
NOTE:
1. All the parts (if any) of each Question must be attempted at one place instead of at different places.
2. Write Q. No. in the Answer Book in accordance with Q. No. in the Q. Paper.
3. No Page/Space be left blank between the answers. All the blank pages of Answer Book must be crossed.
4. Extra attempt of any question or any part of the question will not be considered.
NOTE: Attempt FIVE Questions. Attempt in Urdu or English.
Q. No.1
a) What is meant by seed dormancy? Enlist and explain different causes of seed dormancy
b) What role do auxins perform in various developmental phenomena in plants?
(10+10=20 Marks)
Q. No.2
Write short notes on the following:
(i) Day neutral plants
(ii) Photoperiodic induction
(iii) Long day plants
(iv) Short day plants
(5×4=20 Marks)
Q. No.3
What is meant by salinity? Give causes and effects of salinity and suggest some measures for reclamation of saline soil.
(20 Marks)
Q. No.4
a) Compare the process of mitosis and meiosis in detail.
b) Explain the significance of the process of meiosis for plants.
c) Write a note on ribosomes.
(10+5+5=20 Marks)
Q. No.5
a) Suppose that a normal woman marries a man with hemophilia. What is the probability of the couple having a hemophilic son, and hemophilic daughter?
b) In cross between a pure bred, red eyed female fruit fly and a white eyed male, which parent of the male offspring will have white eyes?
(10+10=20 Marks)
Q. No.6
a) What are the properties of genetic code?
b) Write down a note on genomic library.
(10+10=20 Marks)
Q. No.7
a) Briefly give the salient points of Darwin’s theory of natural selection.
b) How can you explain modern synthetic theory of evolution?
(10+10=20 Marks)
Q. No.8
Differentiate between the followings:
(i) Lamarckism vs Darwinism
(ii) Darwinism vs Neo-Darwinism
(iii) Natural Selection Theory vs Artificial Selection theory
(iv) Adaptive mutation vs Normal mutation
(5×4=20 Marks)
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